James Sulzen
11/21/00
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Subscript = CTRL+= Superscript = CTRL+SHIFT+= Font = CTRL+SHIFT+F
s
= CTRL+SHIFT+S S =
ALT+SHIFT+S Ö =
CTRL-SHIFT-R m = CTRL-SHIFT-M
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1 |
Percentile
rank |
Percentile
rank = L%i-1 + i% * (Score – LRLi) / hi
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i=Interval in which Score
falls; i%= i’s % of total; Fi=Cumul. count
0 to I (FN=N); fi= count of items in i; Li/Ui=Lower/upper
score of i; |
36 |
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2 |
Raw
score from % rank |
Scorep=LRL
+ hi*(pN-SFBi)/fi |
(see above also)
Scorep=raw score corresp. to percentile p; p=specified percentile;
N=total samples; SFB=Fi (sum freq below i); |
39 |
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3 |
Mean Median |
Xbar = SX / N Score.50
= median = LRLi + hi * (N/2 – SFB) / fi |
When median score occurs in
interval i (also see above): |
49 |
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4 |
Std
Dev. |
s = Ö [ S [ (X – m)2] / N] = Ö [SS / N] s = Ö [S [ (X – Xbar)2] / (N-1) ] = Ö [SS / (N-1)] |
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56 |
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Computing formula: s = Ö [(S[X2] – (SX)2/N) / (N-1)] |
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5 |
Z
scores |
Z = (X – Xbar) / s |
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68 |
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6 |
T
scores SAT
scores |
T = 10Z + 50 SAT = 100Z + 500 |
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71 73 |
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7 |
Z
scores |
Zx = (X – Xbar) / sx Zy = (Y – Ybar) / sy |
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109 167 |
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8 |
Std
Err of the Mean |
sXbar = s / ÖN z = (Xbar - m ) / sXbar when s is known t = (Xbar - m ) / SXbar when s
not known |
- Std. Dev. Of sample
means - Z score of sample mean - t score of sample mean (df=N-1) |
119 127 129 |
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9 |
Confidence
Interval of sample mean |
Xbar – tsXbar £ m £ Xbar + tsXbar |
df = N-1 |
134 |
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10 |
Std
Err. of Proportion |
z = (p - p) / sp sp = Ö[p (1-p)/N] (sp = std. err. of a proportion) |
p = proportion of observed
sample p = hypothesized value of population prop. |
136 |
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11 |
Std.
Err. of the Diff of two popul. means |
s2pooled
= (Nc-1)sc2
+ (Nx-1)sx2 scbar-xbar = Ö[ s2pooled (1/Nc + 1/Nx) ] = Ö[ s2pooled (Nc+Nx)/NcNx] |
Assume two populations, mc & mx, and sc & sx (control &
experimental). |
150 |
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12 |
Signif.
of diff’s of two pop.’s |
t = (Xcbar
– Xxbar) / scbar-xbar with df = N-2 Note: N’s and s’s should be approx. equal
(see bottom of p. 156) |
Test: H0 : mx = mc, H1 : mx ¹ mc |
151 |
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Confidence
interval |
[(Xcbar
– Xxbar) – tscbar-xbar] £ mc-mx
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The presumption is that
the two population means are equal so that mc-mx
= 0. |
154 |
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13 |
Matched
Pairs |
t = (Dbar - mD)
/ Ö[sD2/N] (df=N-1) |
Dbar = SDX/N |
157 159 |
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Computing
formula: |
D=X1-X2 |
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14 |
Pearson
rZ |
rxy = 1 – 0.5 * ( S[ (Zx – Zy)2 ] / N) = S[(X-Xbar)(Y-Ybar)] / NsXsY = S [ZxZy] / N |
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169 |
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15 |
Pearson
r. |
rxy
= N S [XY] – SX SY Ö [ (N S X2 – (S X) 2) (N S Y2 – (S Y) 2) ] |
Computing formula |
172 |
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16 |
Corr. |
Significance of correlation: t = r Ö [N-2] / Ö [1-r2] |
df = N-2; use Table D (for Pearson). |
175 |
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17 |
Regression |
Y’ = bXYX + aXY bYX = rxy
(sy / sx ) aYX = Ybar - bXYXbar |
Z’Y = rXYZX |
182 |
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18 |
Std
err. of Estimate of Correlation |
sY’ = sY Ö [ 1 – rxy2 ] = Ö [ S [Y-Y’]2 / N ] rxy2 = [sY2 –sY’2] / sY2 |
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186 187 |
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sY’ = Ö [ S [(Y – Y’)2] / (N – 2) ] |
When s & m aren’t known |
189 |
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19 |
Spearman
Correlation |
rs = 1 – (6S[(Xi-Yi)^2] / (N*(N^2 – 1)) |
When data items are ranked
1® N Use Table E to test
significance |
195 |
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20 |
Point
Biserial Correlation |
rpb = [(Y1bar – Y0bar)/sY] * Ö[pq] |
Correlates bi-discrete
(M/F) & continuous samples (test scores) Use Table D for significance
testing |
197 |
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21 |
Strength
of significance |
rpb
= Ö[
t2 / (t2 + df) ]
where df = N1 + N2 -
2 |
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199 |
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22 |
ANOVA |
SST = S [X – Xbar]2 = SSB + SSW = SX2 – (SX)2/N (computing formula) |
H0 : m1=m2=m3=…mk H1 : At least one
of the m’s not equal k = # of groups; N = total # of samples; Xbar = total mean across
all samples; NG = Size of
group G; XbarG =mean of
grp G; XG = samples in
group G Procedure: Compute F and
compare with .05 or .01 significance value from Table F in book. If computed value > Table F, reject H0. Assumptions (p. 239):
Independent samples; equal variances (or NG’s approx. equal);
normal populations. |
228- |
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SSB = SG [ NG (XbarG – Xbar)2 ] = SkG [ (SXG)2/NG ] – (SX)2/N (computing formula) |
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SSW = SkG [ S[XG – XbarG]2 ] = SST – SSB (computing formula) |
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MSB = SSB / dfB = SSB / (k - 1) dfB=k-1 MSW = SSW / dfW = SSW / (N – k) dfW=N-k |
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F = MSB / MSW = SSB(N-k) / SSW(k-1) |
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23 |
Protected
t test |
t = (Xbari
– Xbarj) / Ö[MSW(1/Ni+1/Nj)] Use to perform pairwise t
test of means across all groups or across all groups of interest. |
Can only be used if F test
H0 is rejected! Perform pairwise t test
among all groups. Not recommended for over
six groups or so (p. 237). |
234-236 |
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Confidence
interval of protected t test |
(Xbari
– Xbarj) – tsxbarI-xbarJ £
mi
- mj
where sxbarI-xbarJ
= Ö[MSw(1/Ni
+ 1/Nj) |
and df = dfW |
238 |
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24 |
Least
significant difference (LSD) of pairwise t test |
LSD = t Ö [
MSw(2/Ni) ]
Ni
= group size
df = N – k Procedure: Look up t value for a & df. Multiply times the expression; result
is min t value that any pairwise t test of the menas must achieve to have
significance. |
Can use LSD if all group sizes are equal. LSD = min t value that must be achieved for significance. |
237 |
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25 |
Strength
of F test |
e = Ö[
dfB(F-1)/(dfBF + dfW) ] |
Produces a correlation
coef. (??) which gives measure with the same meaning as rpb which
shows strength of the relationship. |
239 |
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Which Correlation Techniques to use
(p. 203)
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Var A
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Continuous |
Dichotomous(normal) |
Dichotomous (not normal) |
Var B |
Continuous |
Pearson |
Biserial |
Point biserial |
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Dichotomous (normal) |
Biserial |
Tetrachoric |
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Dichotomus (~normal) |
Point biserial |
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phi |
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